This is a trivial matter as we throw out show that for n 1 , the sum of the first 1 even so numbers is 2 Looking at the formula (1 (1 2 2 , the theorem holds for the base truth . We can even verify this for the first seven even integersN Integers sum total n (n 11 2 2 22 2 4 6 63 2 4 6 12 124 2 4 6 8 20 205 2 4 6 8 10 30 306 2 4 6 8 10 12 42 427 2 4 6 8 10 12 14 56 56 We now engage that the theorem is valid for any n . We can express this mathematically as (Equation 1We must now show that the case for n n 1 holds straight if Equation 1 is trueWe start out the final term in the summationWe subtract (2n 2 ) from each(prenominal) sideQ .E .DWe see that the case for n 1 does hold true if we assume that our! theorem is true...If you want to get a rise essay, lodge it on our website: OrderEssay.net
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